Questions
Percentage error in measuring the force constant and elongation of a spring are respectively 1% and 0.5% then maximum possible percentage error in the elastic potential energy stored in the spring is
detailed solution
Correct option is D
U=12kx2∴ (ΔUU)max×100%=Δkk×100%+2(Δxx)×100%=1%+2×0.5%=2%Talk to our academic expert!
Similar Questions
A physical quantity P is given by . The quantity which brings in the maximum percentage error in P is
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