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A perfect gas goes from state A to another state B by absorbing 8X105 J of heat and doing 6X105 J of external work. It is now transferred between the same two states in an other process in which it absorbs 105 J of heat. In the second process

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a

work done by gas is 105 J

b

work done on gas is 105 J

c

work done by gas is 0.5 X105 J

d

work done on the gas is 0.5x 105 J

answer is B.

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Detailed Solution

In the first processΔU=8×105−6×105J=2×105JFor the second processQ′=ΔU+W′⇒W′=105−2×105J=−105J

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