A perfect gas goes from state A to state B by absorbing $$8$$ X $$105$$ J of heat and doing $$6.5$$ x $$105$$ J of external work. It is now transferred between the same two states in another process in which it absorbs $$105$$ J of heat. In the second process

Question

A perfect gas goes from state A to state B by absorbing $$8$$ X $$105$$ J of heat and doing $$6.5$$ x $$105$$ J of external work. It is now transferred between the same two states in another process in which it absorbs $$105$$ J of heat. In the second process

Infinity Learn · Accepted Answer

According to first law of thermodynamics,$$dU=dQ$$−$$dWdU=8$$×$$105$$−$$6.5$$×$$105=1.5$$×$$105JIn$$ the second process, dU remains the same.∴ $$dW=dQ$$−$$dU=1$$×$$105$$−$$1.5$$×$$105dW=$$−$$0.5$$×$$105J$$∴   Work done on the gas is  $$0.5$$×$$105J$$

A perfect gas goes from state A to state B by absorbing 8 X $10^{5}$ J of heat and doing 6.5 x 10⁵ J of external work. It is now transferred between the same two states in another process in which it absorbs 10⁵ J of heat. In the second process

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A perfect gas goes from state A to state B by absorbing 8 X 105 J of heat and doing 6.5 x 105 J of external work. It is now transferred between the same two states in another process in which it absorbs 105 J of heat. In the second process

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Ready to Test Your Skills?

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A perfect gas goes from state A to state B by absorbing 8 X $10^{5}$ J of heat and doing 6.5 x 10⁵ J of external work. It is now transferred between the same two states in another process in which it absorbs 10⁵ J of heat. In the second process