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Q.

A perfect gas goes from state A to state B by absorbing 8 X 105 J of heat and doing 6.5 x 105 J of external work. It is now transferred between the same two states in another process in which it absorbs 105 J of heat. In the second process

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a

work done on the gas is 105 J

b

work done on the gas is 0.5 X 105 J

c

work done by the gas is 105 J

d

work done by the gas is 0.5 X 105 J

answer is B.

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Detailed Solution

According to first law of thermodynamics,dU=dQ−dWdU=8×105−6.5×105=1.5×105JIn the second process, dU remains the same.∴ dW=dQ−dU=1×105−1.5×105dW=−0.5×105J∴   Work done on the gas is  0.5×105J
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