First slide

Simple hormonic motion

Question

The period of oscillation of a particle in SHM is 4 sec and its amplitude of vibration is 4 cm. The distance of the particle 0.5 s after passing the mean position is

Easy

A

1.33 cm
B

2 cm
C

2√2 cm
D

2√3 cm

Solution

$At t = \frac{T}{8}, y = \frac{A}{\sqrt{2}}$

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