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Q.

The period of oscillation of a simple pendulum in the experiment is recorded as 2.63s, 2.56s, 2.42s, 2.71s and 2.80s respectively. The average absolute error is:

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a

0.1s

b

0.11s

c

0.01s

d

1.0s

answer is B.

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Detailed Solution

Average value =2.63+2.56+2.42+2.71+2.805= 2.62 secNow, ΔT1=2.63−2.62=0.01ΔT2=2.62−2.56=0.06ΔT3=2.62−2.42=0.20ΔT4=2.71−2.62=0.09ΔT5=2.80−2.62=0.18Mean absolute errorΔT=ΔT1+ΔT2+ΔT3+ΔT4+ΔT55=0.545=0.108=0.11sec

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The period of oscillation of a simple pendulum in the experiment is recorded as 2.63s, 2.56s, 2.42s, 2.71s and 2.80s respectively. The average absolute error is: