Questions
The period of oscillation of a simple pendulum is . Measured value of ‘L’ is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stop watch of 0.01s resolution. The percentage error in the determination of ‘g’ will be:
detailed solution
Correct option is C
g=4π2LT2 ⇒Δgg×100=ΔLL+2ΔTT×100=10−31+20.011.95×100=1.13%Talk to our academic expert!
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The density of a cube is measured by measuring its mass and length of its sides. If the maximum errors in the measurement of mass and length are 3% and 2% respectively, then the maximum error in the measurement of density is
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