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The period of oscillations of a magnetic needle in a magnetic field is 1.0 s. If the length of the needle is halved by cutting it, the time period will be

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a
1.0 s
b
0.5 s
c
0.25 s
d
2.0 s

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detailed solution

Correct option is B

T=2πIMB=2πwl2/12Pole Strength x l x B∴T∝wl∴T2T1=w2w1 xl2l1 =w1/2w1 xl1/2l1 =12⇒T2=T12=0.5 s

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