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The period of oscillations of a magnetic needle in a magnetic field is 1.0 s. If the length of the needle is halved by cutting it, the time period will be
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Correct option is B
T=2πIMB=2πwl2/12Pole Strength x l x B∴T∝wl∴T2T1=w2w1 xl2l1 =w1/2w1 xl1/2l1 =12⇒T2=T12=0.5 s
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The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be
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