Download the app

Questions  

The period of revolution of a planet around the sun in circular orbit is same as that of period of similar planet revolving around a star of twice the radius of first orbit and ‘M’ is the mass of the sun and mass of star is

a
2M
b
4M
c
8M
d
16M

detailed solution

Correct option is C

Gravitational force provide centripetal force, mrω2 =GMmr2 ⇒ω2=GMr3⇒ω=GMr3⇒2πT=GMr3⇒T=2πr3GMT∝r3M ⇒T2T1=r2r13M1M2⇒1=2r1r13M1M2⇒1=23M1M2⇒M2=8M1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the following four periods     
(i) Time of revolution of a satellite just above the earth’s surface  (Tst)
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth  (Tma)
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg  (Tsp)
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field  (Tis)
 


phone icon
whats app icon