The period of the satellite of the earth orbiting very near to the surface of the earth is T0. What is the period of the geostationary satellite in terms of T0?
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a
T07
b
7 T0
c
7 T0
d
77 T0
answer is D.
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Detailed Solution
Radius of geostationary satellite is approx 7R.As per Kepler's Law,T2∝r3∴T02∝R3Also, Ts2∝(7R)3⇒(TsT0)2=73⇒Ts=77 T0