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The period of the satellite of the earth orbiting very near to the surface of the earth is $T_{0}$ . What is the period of the geostationary satellite in terms of $T_{0}$ ?

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T07

7 T0

77 T0

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detailed solution

Correct option is D

Radius of geostationary satellite is approx 7R.As per Kepler's Law,T2∝r3∴T02∝R3Also, Ts2∝(7R)3⇒(TsT0)2=73⇒Ts=77 T0

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The period of the satellite of the earth orbiting very near to the surface of the earth is T0. What is the period of the geostationary satellite in terms of T0?

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The period of the satellite of the earth orbiting very near to the surface of the earth is $T_{0}$ . What is the period of the geostationary satellite in terms of $T_{0}$ ?