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The period of a satellite of the earth very near to the surface of the earth is $T_{0} .$ What is the approximate period of the geostationary satellite in terms of $T_{0} ?$ (Height of geostationary satellite above the surface of earth is 36000km)

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T0/7

7T0

77T0

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detailed solution

Correct option is D

T2 α r3, R=6400 km∴ r = (6400 + 36000) km = 42,400 km∴ TT0=rR3/2=4240064003/2 ⇒ T ≈ 77T0

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The period of a satellite of the earth very near to the surface of the earth is T0. What is the approximate period of the geostationary satellite in terms of T0? (Height of geostationary satellite above the surface of earth is 36000km)

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The period of a satellite of the earth very near to the surface of the earth is $T_{0} .$ What is the approximate period of the geostationary satellite in terms of $T_{0} ?$ (Height of geostationary satellite above the surface of earth is 36000km)