First slide

Simple hormonic motion

Question

The period of a simple pendulum of length L at aplace where the acceleration due to gravity is g is T. What is the period of a simple pendulum of the same length at a place where the acceleration due to gravity is 1.02 g?

NA

Solution

$T \propto \frac{1}{\sqrt{g}} \Rightarrow g$ g increases then T decreases.

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