Questions
The period of a simple pendulum measured inside a stationary lift is ‘T’. If the lift starts moving upwards with a acceleration g/3. What will be the time period.
detailed solution
Correct option is C
time period of simple pendulum is T=2πlg given acceleration of lift in which pendulum is oscillating is a=g3new time period of simple pendulum is T1=2πlg+a=2πlg+g/3 on substituting a=g3, now divide the equations of T and T1 T1T=gg+a=gg+g/3=3g4g ⇒T1T=34 ⇒T1=3/2 TTalk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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