Questions
The period of a simple pendulum measured inside a stationary lift is ‘T’. If the lift starts moving upwards with a acceleration g/3. What will be the time period.
detailed solution
Correct option is C
T=2πlg given a=g3 T1=2πlg+a T1T=gg+a=gg+g/3=3g4g =34 T1= 3T2Similar Questions
A simple pendulum is hanging from a peg inserted in a vertical wall. Its bob is stretched in horizontal position from the wall and is left free to move. The bob hits on the wall the coefficient of restitution is . After how many collisions the amplitude of vibration will become less than 60°
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