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Q.

The period of a simple pendulum measured inside a stationary lift is ‘T’. If the lift starts moving upwards with a acceleration g/3. What will be the time period.

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a

T3

b

3T

c

3T2

d

32T

answer is C.

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Detailed Solution

T=2πlg given a=g3 T1=2πlg+a T1T=gg+a=gg+g/3=3g4g =34 T1= 3T2

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The period of a simple pendulum measured inside a stationary lift is ‘T’. If the lift starts moving upwards with a acceleration g/3. What will be the time period.