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The period of a simple pendulum measured inside a stationary lift is ‘T’. If the lift starts moving upwards with a acceleration g/3. What will be the time period.

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a
T3
b
3T
c
3T2
d
32T

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detailed solution

Correct option is C

T=2πlg  given a=g3 T1=2πlg+a T1T=gg+a=gg+g/3=3g4g =34 T1=   3T2


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