First slide

Ray optics

Question

A person can not see the objects beyond 50 cm. The power of a lens to correct this vision will be

Moderate

A

+2 D
B

-2 D
C

+5 D
D

0.5 D

Solution

$U = \infty, f = V = - 50 cm$
$P = \frac{1}{f_{(m)}}$
$\frac{100}{f (cm)} = \frac{- 100}{50} = - 2 D$

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