Q.

A person can see clearly objects only when they lie between 50 cm and 400 cm  from his eyes.  In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be

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a

convex, +2.25 D

b

concave, −0.25 D

c

concave, −0.2 D

d

convex, +0.15 D

answer is B.

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Detailed Solution

Image distance, v=400cm=4m⇒u=∞ Using lens equation, 1v−1u=1f⇒1−4−1∞=1f⇒f=−4m Now, power of the required lens is, P=1f=1−4=−0.25D Thus, the person require a concave lens of power −0.25D .
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