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Q.

A person can throw a stone to a maximum height of h metre. The maximum distance to which he can throw the stone is:

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a

h

b

h2

c

2h

d

3h

answer is C.

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Detailed Solution

Height H is given byH = u2 sin2θ2gWhen θ = 900, H = Hmax = u22g= hRange is given by: R = u2sin 2θgNow Rmax = u2g(when θ = 450) = 2h
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