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A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/hour. The speed of sound in air is $345 {ms}^{- 1}$ . The number of beats heard by him is

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detailed solution

Correct option is C

According the concept of sound imagen'=v+vpersonv−vpersonn=345+5345−5×272=280 HzΔn=Number of beats =280 – 272 = 8 Hz

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A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/hour. The speed of sound in air is 345 ms−1. The number of beats heard by him is

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A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/hour. The speed of sound in air is $345 {ms}^{- 1}$ . The number of beats heard by him is