Questions
A person feels 2.5% difference of frequency of a motor-car horn. If the motor-car is moving to the person and the velocity of sound is 320 m/sec, then the velocity of car will be
a
8 m/s (approx.)
b
800 m/s
c
7 m/s
d
6 m/s (approx.)
detailed solution
Correct option is A
By Doppler’s formula n'=nv(v−vS)Since, source is moving towards the listener so n'>n.If n = 100 then n' = 102.5⇒102.5=100×320(320−vS)⇒vs=8 m/sec (approx.)Talk to our academic expert!
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An observer is moving towards the stationary source of sound, then
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