A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth surface and fires 10 shots horizontally, in 5 s. Each bullet has a mass of 10 g with a muzzle velocity of 800 ms-1. The final velocity acquired by the person and the average force exerted on the person are
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a
-0.08 ms-1,16 N
b
-0.8 ms-1,8 N
c
-1.6 ms-1,16 N
d
-1.6 ms-1,8 N
answer is A.
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Detailed Solution
0=nmu + (M-nm)v ⇒0=10×101000×800 + (100-10×101000)v ⇒v=-8099.9=-0.8 m/s Average force exerted = 10×0.01×8005=16N