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Q.

A person initially at rest throws a ball upward with speed 10 m/s at angle 37o with horizontal. He tries to catch the ball. For this, he accelerates just after he throws the ball, with constant acceleration for 1 sec and then continues to run at a constant speed and catches the ball exactly at the same height he throws the ball. Choose the correct option(s). (Use g = 10m/s2)

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a

Constant speed of person is approx. 13.7 m/s

b

Acceleration of person is 15.2 m/s2

c

Acceleration of person is approx. 13.7 m/s2

d

Speed of person is 23 m/s

answer is A.

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Detailed Solution

Time of flight (T)=2(10)sin⁡37∘10=1.2secRange, R=102sin⁡237∘10=9.6mNow 12a(1)2+v(0.2)=9.6        0.5a+0.2v=9.6 ..........(i)Also v=u+at         v=0+a(1)=a  .........(ii)From (i) and (ii): v=a=967≅13.7
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