A person of mass m is on the floor of a lift.The lift is moving down with an acceleration ‘a’. Then :a) the net force is acting in downward direction and is equal to mgb) the force mg must be greater than reaction forcec) the man appears to be lighter than his true weight by a factor (a/g)
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
a, b, c are correct
b
b and c are correct
c
a and c are correct
d
only b is correct
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
As observed from the ground , net force = (mg-N)=maAs observed from the lift , net force = N+ma -mg=0 ⇒ N = mg-ma < mgApparent weight = N < mg