Questions
A person of mass m is on the floor of a lift.The lift is moving down with an acceleration ‘a’. Then :
a) the net force is acting in downward direction and is equal to mg
b) the force mg must be greater than reaction force
c) the man appears to be lighter than his true weight by a factor (a/g)
detailed solution
Correct option is B
As observed from the ground , net force = (mg-N)=maAs observed from the lift , net force = N+ma -mg=0 ⇒ N = mg-ma < mgApparent weight = N < mgTalk to our academic expert!
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