Questions
A person measures the depth of a well by measuring the time interval between dropping a stone and receiving the sound of impact with the bottom of the well. The error in his measurement of time is seconds and he measures the depth of the well to be meters. Take the acceleration due to gravity and the velocity of sound is . Then the fractional error in the measurement, , is closest to
detailed solution
Correct option is A
2Lg+LV=T After differentiating, ⇒2gdL2L+0=dT dLV≈0⇒12gdLL=dT After integrating, ⇒L=12gT2⇒T=2Lg=2×2010=2sA/SO,dLL=2dTT=2×0.012=0.01⇒dLL×100=1%Similar Questions
To estimate 'g' , error in measurement of L is 2% and error in measurement of T is 3%. The error in estimated 'g' will be:
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests