Newton's laws of motion

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Question

A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 $m / s^{2}$ will be _______N. $[g = 10 m / s^{2}]$

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Solution

$\begin{array}{l} Given mass = m = 60 kg \\ Now in an downward accelerating lift w^{1} = m (g - a) \\ \Rightarrow w^{1} = 60 (10 - 1.8) N = 60 \times 8.2 N = 492 N \end{array}$

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