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Q.

A person is throwing two balls in the air one after the other. He throws the second ball when the first ball is at the highest point. If he is throwing the balls every second, how high do they rise?

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a

5m

b

3.75 m

c

2.50 m

d

1.25 m

answer is A.

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Detailed Solution

Time of ascent =1s⇒ug=1⇒u=10ms−1 Maximum height attained =u22g=1022×10=5m
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A person is throwing two balls in the air one after the other. He throws the second ball when the first ball is at the highest point. If he is throwing the balls every second, how high do they rise?