First slide

Projection Under uniform Acceleration

Question

A person throws a stone with a velocity 10 m/s at an angle $\tan θ = 3 / 4$ to horizontal from a point at distance 8 m from the wall. The stone just passes over the wall. The height of the wall is [g = 10m/ s² ]

Moderate

A

2 m
B

1 m
C

4 m
D

none

Solution

$y = xtan θ - \frac{1}{2} g \frac{x^{2}}{u^{2} \cos^{2} θ} \tan θ = \frac{3}{4}$
$\begin{array}{l} \cos θ = \frac{4}{5} \\ = 8 \frac{3}{4} - \frac{1}{2} 10 \frac{64}{100 \frac{16}{25}} \end{array}$
= 6 -5 = 1 m

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