Questions
A person travelling at 43.2 km/h applies the brake giving a deceleration of to his scooter. How far will he travel before stopping?
detailed solution
Correct option is D
given Initial velocity u=43.2km/h=43.2×518=12m/su=12m/s;final velocity =v=0final velocity =v=0a=−6m/s2 ( deceleration )equation of motion , v2−u2=2aSS=v2−u22a Distance S=02−1222(−6)=12mTalk to our academic expert!
Similar Questions
A particle is moving along the x-axis whose acceleration is given by , where x is the location of the particle. At t = 0, the particle is at rest at x = 4/3 m. The distance travelled by the particle in 5 s is
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