A person travelling at 43.2 km/h applies the brake giving a deceleration of 6 m/s2 to his scooter. How far will he travel before stopping?

given  Initial velocity u=43.2km/h=43.2×518=12m/su=12m/s;final velocity =v=0final velocity =v=0a=−6m/s2        ( deceleration )equation of motion ,   v2−u2=2aSS=v2−u22a Distance S=02−1222(−6)=12m