First slide

The optical instruments

Question

A person uses a lens of power + 3D to normalise vision. Near point of hypermetropic eye is

Moderate

A

1 m
B

1.66 m
C

2 m
D

0.66 m

Solution

$Focal length of the lens f = \frac{100}{3} cm By lens formula \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{+ 100 / 3} = \frac{1}{v} - \frac{1}{- 25} \Rightarrow v = - 100 cm = - 1 m$

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