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Q.

A person walks along a straight road from his house to a market 2.5kms away with a speed of 5 km/hr and instantly turns back and reaches his house with a speed of 7.5 kms/hr. The average speed of the person during the time interval 0 to 50 minutes is (in m/sec)

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a

423

b

5/3

c

5/6

d

1/3

answer is B.

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Detailed Solution

Time required to reach market = 30 min = 1/2hrremaining time = 50 – 30 = 20 mindistance in next 20 min = 7.5×2060=2.5 km ∴vavg=2v1v2v1+v2=2×5×7.55+7.5=6 km/hr ∴vavg=6×518m/sec = 53m/sec

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A person walks along a straight road from his house to a market 2.5kms away with a speed of 5 km/hr and instantly turns back and reaches his house with a speed of 7.5 kms/hr. The average speed of the person during the time interval 0 to 50 minutes is (in m/sec)