First slide

Motion of planets and satellites

Question

A person will get less quantity of matter in kg –wt. at

Easy

A

Poles
B

At latitude of $60^{o}$
C

Equator
D

Satellite

Solution

$g_{λ} = g - R ω^{2} \cos^{2} λ A t e q u a t o r : λ = 0 \Rightarrow g_{λ} = g - R ω^{2} \cos^{2} 0 = g - R ω^{2} A t P o l e s : λ = 90 \Rightarrow g_{λ} = g - R ω^{2} \cos^{2} 90 = g A t 60 ° : λ = 60 \Rightarrow g_{λ} = g - R ω^{2} \cos^{2} 60 = g - R ω^{2} {(\frac{1}{2})}^{2} = g - \frac{R ω^{2}}{4} I n s a t e l l i t e : g = 0 . A b o d y w e i g h s z e r o r e a d i n g i n s a t e l l i t e$

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