Questions
A 400 pF capacitor is charged with a 100 V battery. After disconnecting battery this capacitor is connected with another 400 pF capacitor. Then find out energy loss.
detailed solution
Correct option is A
Energy loss = C1C22C1+C2V1-V22 =400 x 10-124100-02J=1 x 10-6 JTalk to our academic expert!
Similar Questions
Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
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