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The phase difference between two points separated by 0.8 m in a wave of frequency is 120 Hz is $\frac{π}{2}$ . The velocity of wave is

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720 m/s

384 m/s

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1 m/s

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detailed solution

Correct option is B

Phase difference =2πλ×path difference ⇒π2=2πλ×0.8⇒λ=4×0.8=3.2 m Velocity v=nλ=120×3.2=384 m/s.

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The phase difference between two points separated by 0.8 m in a wave of frequency is 120 Hz is π2. The velocity of wave is

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The phase difference between two points separated by 0.8 m in a wave of frequency is 120 Hz is $\frac{π}{2}$ . The velocity of wave is