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Q.

The  phase  difference  between  two  waves  represented  by   y1=10−6sin[100 t+(x/50)+0.5]m y2=10−6cos [100 t+(x/50)]mwhere x is expressed in metres and t is expressed in seconds, is approximately

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a

1.5 rad

b

1.07 rad

c

2.07 rad

d

0.5 rad

answer is B.

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Detailed Solution

y1=10−6sin [100 t+(x/50)+0.5]y2=10−6sin 100 t+x50+π2Phase difference ϕ=100t+(x/50)+1.57-100t+(x/50)+0.5 =1.07radians.
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The  phase  difference  between  two  waves  represented  by   y1=10−6sin[100 t+(x/50)+0.5]m y2=10−6cos [100 t+(x/50)]mwhere x is expressed in metres and t is expressed in seconds, is approximately