In a photo electric experiment, the metal surface is illuminated by a beam of light of intensity I and frequency ν. Maximum kinetic energy of photo electron is found to be Km. Keeping the intensity unchanged, if another light of frequency ν/2 is used in the same experimental set up, then saturated photo current
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a
remains unchanged
b
becomes double
c
becomes 1.5 times the initial value
d
becomes 3 times the initial value
answer is B.
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Detailed Solution
Intensity I = n. hν. where n is the number of photons crossing the cross section of incident beam in unit time. When ν1=ν2, I1=I=n1hν2⇒n1=2nHence saturated photo current is doubled.