In a photo electric experiment, the metal surface is illuminated by a beam of light of intensity I and frequency ν. Maximum kinetic energy of photo electron is found to be Km. Keeping the intensity unchanged, if another light of frequency ν/2 is used in the same experimental set up, then saturated photo current

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remains unchanged

becomes double

becomes 1.5 times the initial value

becomes 3 times the initial value

answer is B.

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Detailed Solution

Intensity I = n. hν. where n is the number of photons crossing the cross section of incident beam in unit time. When ν1=ν2, I1=I=n1hν2⇒n1=2nHence saturated photo current is doubled.

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