Questions
In a photo electric experiment when a light of wavelength 4000 is used, stopping potential is found to be 0.82 volt. Again when light of wave length 3000 is used stopping potential is found to be 1.85 volt. Then find the value of plank's constant.
detailed solution
Correct option is C
hcλ1=ϕ+eV1 and hcλ2=ϕ+eV2∴ hcλ2−hcλ1=e(V2−V1)⇒h×3×108(13×10−7−14×10−7)=1.6×10−19×(1.85−0.82)⇒h×3×10812×10−7=1.6×10−19×1.03⇒h=1.6×1.03×123×10−34J−S=6.592×10−34J−SAlternative solution :- Just check the power.Talk to our academic expert!
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