Download the app

Questions  

In a photo electric experiment when a light of wavelength 4000 Ao is used, stopping potential is found to be 0.82 volt. Again when light of wave length 3000 Ao is used stopping potential is found to be 1.85 volt. Then find the value of plank's constant. 

a
6.684×10−35J−S
b
6.712×10−32J−S
c
6.592×10−34J−S
d
6.428×10−36J−S

detailed solution

Correct option is C

hcλ1=ϕ+eV1 and hcλ2=ϕ+eV2∴ hcλ2−hcλ1=e(V2−V1)⇒h×3×108(13×10−7−14×10−7)=1.6×10−19×(1.85−0.82)⇒h×3×10812×10−7=1.6×10−19×1.03⇒h=1.6×1.03×123×10−34J−S=6.592×10−34J−SAlternative solution :- Just check the power.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Light described at a place by equation E=200vmsin2×1015s1t+sin10×1015s1t   falls on metal surface having work function 2 eV, the maximum kinetic energy of photoelectrons?


phone icon
whats app icon