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Q.

In a photo electric experiment when a light of wavelength 4000 Ao is used, stopping potential is found to be 0.82 volt. Again when light of wave length 3000 Ao is used stopping potential is found to be 1.85 volt. Then find the value of plank's constant.

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a

6.684×10−35J−S

b

6.712×10−32J−S

c

6.592×10−34J−S

d

6.428×10−36J−S

answer is C.

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Detailed Solution

hcλ1=ϕ+eV1 and hcλ2=ϕ+eV2∴ hcλ2−hcλ1=e(V2−V1)⇒h×3×108(13×10−7−14×10−7)=1.6×10−19×(1.85−0.82)⇒h×3×10812×10−7=1.6×10−19×1.03⇒h=1.6×1.03×123×10−34J−S=6.592×10−34J−SAlternative solution :- Just check the power.
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