Questions
In a photo electric experiment, the work function of the illuminated metal surface is equal to half of the energy of individual photon of the light used and stopping potential is found to be 1.5 volt. Then wavelength of the light used is
detailed solution
Correct option is A
hv=ϕ+kmax⇒hv=12hv+kmax∴ kmax=hv2=hc2λ, But kmax=ev0∴ hc2λ=ev0⇒λ=hc2(ev0)=124202×1.5 Ao⇒λ=4140 AoTalk to our academic expert!
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