In a photo electric experiment, work function of a target metal is 1ev and wavelength of light used in the experiment is 3000AoThen stopping potential will be
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answer is 2.
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Detailed Solution
Energy of incident photon, hν=hcλ=123753000ev=4.125 evNow hν=ϕ+ev0⇒V0=4.125−1eev=3.125V