First slide

Photo Electric Effect

Question

In a photo-electric cell, the wavelength of incident light is changed from 4000 $Å$ to 3000 $Å$ then change in stopping potential will be

Easy

A

0.66 V
B

1.03 V
C

0.33 V
D

0.49 V

Solution

The change in stopping potential
$= \frac{hc}{e} [\frac{1}{λ_{2}} - \frac{1}{λ_{1}}] = \frac{(6 \cdot 6 \times 10^{- 34}) (3 \times 10^{8})}{(1 \cdot 6 \times 10^{- 19})} [\frac{10^{10}}{3000} - \frac{10^{10}}{4000}] = 1.03 V$

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