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Q.

In photoelectric effect of a certain metal the stopping potential is 0.7 V if the wavelength of incident radiation is 500 nm. Now the stopping potential comes out to be 1.4 V if the wavelength of incident radiation is:

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a

390 nm

b

352 nm

c

275 nm

d

422 nm

answer is A.

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Detailed Solution

hcλ=ϕ+eVs.⇒1240500=ϕ+0.7 1240λ=ϕ+1.4⇒12401λ−1500=0.7⇒λ=390nm
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