In a photoelectric effect, electrons are emitted
with a maximum velocity proportional to the frequency of the incident radiation
at a rate that is independent of the intensity of the incident radiation
only if the frequency of the incident radiation is above a certain threshold value
only if the temperature of the emitter is high
KEmax=hv−ϕ⇒ 12mvmax2=hv−ϕ⇒vmax=2(hv−ϕ)m
Hence, (a) is incorrect.Since n = (IA/hv), therefore rate of emission of electrons is proportional to the intensity (I).
KEmax=hv−ϕ
Hence, (c) is true.