In a photoelectric effect, electrons are emitted

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with a maximum velocity proportional to the frequency of the incident radiation

at a rate that is independent of the intensity of the incident radiation

only if the frequency of the incident radiation is above a certain threshold value

only if the temperature of the emitter is high

answer is C.

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Detailed Solution

KEmax=hv−ϕ⇒ 12mvmax2=hv−ϕ⇒vmax=2(hv−ϕ)mHence, (a) is incorrect.Since n = (IA/hv), therefore rate of emission of electrons is proportional to the intensity (I).KEmax=hv−ϕHence, (c) is true.

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