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For photoelectric emission from certain metal the cutoff frequency is $υ$ . If radiation of frequency $2 υ$ impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

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2hυm

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detailed solution

Correct option is A

Work function, ϕ=hνAccording to Einstein's photoelectric equation12mvmax2=h2ν−hν 12mvmax2=hν vmax2=2hνm vmax=2hνm

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For photoelectric emission from certain metal the cutoff frequency is υ . If radiation of frequency 2υ impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

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For photoelectric emission from certain metal the cutoff frequency is $υ$ . If radiation of frequency $2 υ$ impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)