Photoelectric effect and study of photoelectric effect

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Question

In a photoelectric experiment, the collector plate is at 2.0 V with respect to the emitter plate made of copper ( $ϕ$ = 4.5e V). The emitter is illuminated by a source of monochromatic light of wavelength 200 nm. The maximum kinetic energy of the photo electrons reaching the collector is ----eV

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Solution

$\begin{array}{l} {({KE}_{max})}_{emitted} = \frac{hc}{λ} - ϕ = \frac{1240}{200} - 4 .5 = 1 .7 eV \\ ∴ {({KE}_{max})}_{reached} = 1 .7 + 2 = 3 .7 eV \end{array}$

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