Questions
In a photoelectric experiment, with light of wavelength , the fastest electron has speed v. If the exciting wavelength is changed to , the speed of the fastest emitted electron will become-
detailed solution
Correct option is D
12mv2=hcλ−ϕ12mv'2=hc(3λ/4)−ϕ=4hc3λ−ϕ Clearly, v'>43vTalk to our academic expert!
Similar Questions
Figure shows the stopping potential (V)versus frequency (v) graph for photoelectric effect in a metal. From the graph, The Planck's constant (h) is . The value of y is
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