Questions
In a photoelectric experiment, with light of wavelength , the fastest electron has speed v. If the exciting wavelength is changed to the speed of the fastest emitted electron will become
detailed solution
Correct option is D
12 mv2=hcλ −φ12 mv2=hc(3λ/4) − ϕ=4hc3λ − ϕClearly Vmax>43VTalk to our academic expert!
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