First slide

Photo Electric Effect

Question

In a photoelectric experiment work function of the metal surface is 3 eV and stopping potential is 2 volt then what percent of the energy of the photon of incident light appears as kinetic energy of fastest moving photo-electron?

Moderate

A

60%
B

40%
C

30%
D

20%

Solution

$K_{\max} = 2 e V and ϕ = 3 e V$
$∴$ Energy of incident photon, $h υ = ϕ + K_{\max} = 5 e V$
$∴ \frac{K_{\max}}{h υ} = \frac{2}{5} \times 100 % = 40 %$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App