The photoelectric threshold wavelength of silver is $3250 \times 10^{- 10} m$ . The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength $2536 \times 10^{- 10} m is$
$[Given h = 4.14 \times 10^{- 15} eVs and c = 3 \times 10^{8} m s^{- 1}]$

Question

The photoelectric threshold wavelength of silver is $3250 \times 10^{- 10} m$ . The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength $2536 \times 10^{- 10} m is$

$[Given h = 4.14 \times 10^{- 15} eVs and c = 3 \times 10^{8} m s^{- 1}]$

Infinity Learn · Accepted Answer

$$Kmax=hv-$$ϕ$$0=hv-hvo=hc$$λ$$-hc$$λ$$0$$  where λ$$0=$$ threshold wavelength   or $$12mv2=hc$$λ$$-hc$$λ$$0$$  Here, $$h=4.14$$×$$10-15eVs$$,$$c=3$$×$$108$$ m $$s-1$$λ$$o=3250$$×$$10-10$$ $$m=3250A0$$λ$$=2536$$×$$10-10$$ $$m=2536A0$$,$$m=9.1$$×$$10-31$$ $$kghc=4.14$$×$$10-15eVs$$×$$3$$×$$108$$ m $$s-1=12420eV$$\AA∴ $$12mv2=1242012536-13250eV=1.076eVv2=2.152eVm=2.152$$×$$1.6$$×$$10-199.1$$×$$10-31$$∴ v≈$$6$$×$$105$$ m $$s-1=0.6$$×$$106$$ m $$s-1$$

The photoelectric threshold wavelength of silver is $3250 \times 10^{- 10} m$ . The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength $2536 \times 10^{- 10} m is$
$[Given h = 4.14 \times 10^{- 15} eVs and c = 3 \times 10^{8} m s^{- 1}]$

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The photoelectric threshold wavelength of silver is 3250×10-10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536×10-10 m is Given h=4.14×10-15eVs and c=3×108 m s-1

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Ready to Test Your Skills?

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The photoelectric threshold wavelength of silver is $3250 \times 10^{- 10} m$ . The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength $2536 \times 10^{- 10} m is$
$[Given h = 4.14 \times 10^{- 15} eVs and c = 3 \times 10^{8} m s^{- 1}]$