Q.
The photoelectric threshold wavelength of silver is 3250×10-10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536×10-10 m is Given h=4.14×10-15eVs and c=3×108 m s-1
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
≈0.6×106 m s-1
b
≈61×103 m s-1
c
≈0.3×106 m s-1
d
≈6×105 m s-1
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Kmax=hv-ϕ0=hv-hvo=hcλ-hcλ0 where λ0= threshold wavelength or 12mv2=hcλ-hcλ0 Here, h=4.14×10-15eVs,c=3×108 m s-1λo=3250×10-10 m=3250A0λ=2536×10-10 m=2536A0,m=9.1×10-31 kghc=4.14×10-15eVs×3×108 m s-1=12420eV\AA∴ 12mv2=1242012536-13250eV=1.076eVv2=2.152eVm=2.152×1.6×10-199.1×10-31∴ v≈6×105 m s-1=0.6×106 m s-1
Watch 3-min video & get full concept clarity