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 In a photoemissive cell with exciting wavelength λ , the fastest electron has speed v. If the exciting wavelength is changed to 

3\lambda /4

 , the speed of the fastest emitted electron will be       

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detailed solution

Correct option is D

When wavelength is λ  and velocity is v, then ........(i)When wavelength is   and velocity is v’ then .......(ii)Divide equation (ii) by (i), we get


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The maximum energy Kmax of photoelectrons emitted in a photoelectric cells is measured using lights of various frequencies v. The graph in shows how Kmaxvaries with v. The slope of the graph is equal to
 


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