Q.

A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector

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a

2 photon of energy 10.2 eV

b

2 photon of energy of 1.4 eV

c

One photon of energy 10.2 eV and an electron of  energy 1.4 eV

d

One photon of energy 10.2 eV and another photon of 1.4 eV

answer is C.

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Detailed Solution

Due to 10.2 eV photon one photon of energy 10.2 eV will be detected.Due to 15 eV photon the electron will come out of the atom with energy (15 - 13.6) = 1.4 eV
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A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector