A photon and an electron possess same de-Broglie wavelength. Given that c is speed of light and v, the speed of electrons, which of the following relations is correct ? Here Ee = K.E. of electron, Eph = K.E. of photon, pe= momentum of electron, pph = momentum of photon

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Ee/Eph=2cV

Ee/Eph=V2c

pe/pph=2cV

pe/pph=c2v

answer is B.

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Detailed Solution

Ee=12mv2=12(mv)v =12×hλ×V Eph=hcλ ∴ Ee/Eph=V/2c

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