A photon and an electron possess same de-Broglie wavelength. Given that c is speed of light and v, the speed of electrons, which of the following relations is correct ? Here ${\mathrm{E}}_{\mathrm{e}}$ = K.E. of electron, ${\mathrm{E}}_{\mathrm{ph}}$ = K.E. of photon, ${\mathrm{p}}_{\mathrm{e}}$= momentum of electron, ${\mathrm{p}}_{\mathrm{ph}}$ = momentum of photon

• A

  ${\mathrm{E}}_{\mathrm{e}}/{\mathrm{E}}_{\mathrm{ph}}=\frac{2\mathrm{c}}{\mathrm{V}}$

• B

  ${\mathrm{E}}_{\mathrm{e}}/{\mathrm{E}}_{\mathrm{ph}}=\frac{\mathrm{V}}{2\mathrm{c}}$

• C

  ${\mathrm{p}}_{\mathrm{e}}/{\mathrm{p}}_{\mathrm{ph}}=\frac{2\mathrm{c}}{\mathrm{V}}$

• D

  ${\mathrm{p}}_{\mathrm{e}}/{\mathrm{p}}_{\mathrm{ph}}=\frac{\mathrm{c}}{2\mathrm{v}}$