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A photon of energy 10.2 eV collides inelastically with a hydrogen atom in ground state. After a certain time interval of few microseconds another photon of energy 15.0 e V collides inelastically with the same hydrogen atom,then the observation made by a suitable detector is

a
I photon with energy 10.2 eV and electron with energy 1.4 eV.
b
2 photons with energy 10.2 eV
c
2 photons with energy 1.4 eV
d
1 photon with energy 3.4 eV and 1 electron with energy 1.4 eV

detailed solution

Correct option is A

10.2 eV photon on collision will excite hydrogen atom to first excited state but hydrogen atom will return to ground state before next collision. For second photon 15 eV > the ionization energy 13.6 ev' The electron in the ground state n = I) is ionised and the excess energy 15 eV - 13.6 eV = 1.4 eV appears as the kinetic energy of the electron.

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