Photo Electric Effect

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Question

A photon incident on a metal of photo electric work function 2 eV has produced photo electron of kinetic energy 2 eV. The wave length associated with the photon is

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Solution

$E = {W_0} + K{E_{\max }}\,\,;\,\,$
$\therefore \,\,\frac{{hc}}{\lambda } = {W_o} + K{E_{\max }}$
$\therefore \frac{{12400}}{\lambda } = 2 + 2\,\,;\,\,$
$\therefore \lambda = 3100\mathop A\limits^0$

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